There are 11 red checkers and 5 black checkers in a bag. Checkers are selected one at a time, with replacement. Each time, the color of the checker is recorded. Find the probability of selecting a red checker exactly 6 times in 9 selections. Show your work.
Accepted Solution
A:
Answer:P(6 times in 9 selection) = 0.116Step-by-step explanation:There are 11 red checkers and 5 black checkers in a bag soP(red) = no. of red checkers / total no. of checkers = 11/(11+5) = 11/16Checkers are selected one at a time, with replacement. So P(red) is the same for every selection at 11/16.Use binomial distribution to find the probability of selecting a red checker exactly 6 times in 9 selections.In this case, n = 9 and k = 6, P(red)=11/16 soP(6 times in 9 selection) = nCk * P(red)^k * (1-P(red))^(n-k)where 9C7 = 9! / [7!*(9-7)!] = 9! / 7!*2! = 9*8 / 2 =36so P(6 times in 9 selection)= 36 * (11/16)^6 * (5/16)^3= 0.116